80b^2=20

Solution for 80b^2=20 equation:

80b^2=20

We move all terms to the left:

80b^2-(20)=0

a = 80; b = 0; c = -20;
Δ = b2-4ac
Δ = 02-4·80·(-20)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80}{2*80}=\frac{-80}{160}
=-1/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80}{2*80}=\frac{80}{160}
=1/2
$